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Bugatti working on Super Veyron with 1.8-second 0-60 mph time?

At some point, someone is going to have to hand the minds at Bugatti a physics book and tell them to settle down. Automobile reports the monarch of the Volkswagen stable is out to eclipse its own ludicrous performance threshold by building a new Super Veyron capable of snapping to 60 mph in 1.8 seconds. How? The company plans to shove even more carbon fiber at the ultracar while also turning up the horsepower. Rumor has it the machine will boast either an 8.0- or 9.6-liter W16 engine good for 1,600 horsepower, which should be enough to nudge the vehicle's top end from 259 mph all the way to 288 mph.
All told, the Über Veyron will hold a 550-pound advantage over its predecessor for a power to weight ratio of 2.2 lb/hp. How much will one of these things cost you? Expect to pony up $2.5 million for the privilege of ownership. That is, if it makes it to production.

Is a wrecked Bugatti worth $250k?

When a Bugatti Veyron crashed on a highway in Austria a few months ago, insurance company AXA estimated the cost of repairs at upwards of $800,000. Of course, there were worries that even after all the repairs the car may never drive quite the same. So rather than try, the insurance company evidently wrote it off and paid the owner the insured value of the car. But now it's got the wrecked Bugatti on its hands, and is looking to offload it.
This early model, built in 2008, has the original version's 987-horsepower 8.0-liter quad-turbo W16 engine, a fixed roof and a blue and black livery - unlike some more recent examples that have adopted a removable roof panel, employed a more powerful 1,184-hp engine and moved away from the original two-tone paint schemes. It's got nearly 20,000 miles on the odometer and would still require the better part of a million bucks to get it running again... at which point it could be worth more in spare parts, which surely don't come cheap from the manufacturer in Molsheim.
Alternatively, with bidding currently hovering around a quarter million, you could just get yourself a brand spankin' new Ferrari 458 Italia, Lamborghini Huracán or McLaren 650S and actually get to drive it without spending eight hundred grand on repairs. But if you were looking to pick up a Veyron on the cheap, regardless of condition, this could be your chance.

Bugatti has sold all nine of its Legend edition Veyrons

You may have balked at the release of each of Bugatti's Legend edition Veyrons and dismissed them as simple a way for the Alsatian marque to sell the last 50 cars it needs to move before it can put the series to rest. But what you can't argue with is the fact that it's working, because Bugatti has sold every last one of them.
The "Legendes de Bugatti" series launched, as you may recall, with the Jean-Pierre Wimille edition (pictured above and in the updated image gallery) at Pebble Beach this past August. The Jean Bugatti edition followed at the Frankfurt show, and the Meo Costantini edition debuted in Dubai. Each one is based on the Vitesse roadster and comes with a special paint scheme and interior palette created in tribute to a legendary driver from the marque's hey day in pre-war grand prix racing. Each of the three limited runs is limited to three examples, each of which, Bugatti has confirmed, has sold for around 2.2 million euros - equivalent to approximately $3 million at present exchange rates. And here we thought the million-dollar asking price for the original Veyron was a lot.
Before all is said and done, there will be three more of these special series - nine more examples - for a total of eighteen vehicles. Bugatti is set to unveil the fourth version next week in Geneva, anticipated to pay tribute to pioneering female driver Elisabeth Junek. We're still expecting Ettore's son Rembrandt Bugatti to be the subject of another one, leaving the sixth up in the air. Whoever those remaining examples honor, however, you can bet Bugatti will sell them all, which will only bring it closer to selling those last few Veyrons and moving on to its successor, whatever form it may take.